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From the previous step we have erx(6r2 + 3r − 3) = 0. Since erx is never 0, then we know 6r2 + 3r − 3 = 0. Solving the above equation gives the solutions to the quadratic equation.

Respuesta :

Answer:

6r2+3r-3=0

two solutions are possible

r= -1

r=1/2

olayemiolakunle65

Answer:

 r = - 1      or   r = 1/2

Step-by-step explanation:

From the quadratic equation;

                [tex]6r^{2} + 3r - 3 = 0[/tex]

          [tex]6r^{2}[/tex] + 6r - 3r - 3 = 0

           ( [tex]6r^{2}[/tex] + 6r) - (3r + 3) = 0

         6r(r + 1)  - 3 (r + 1) = 0

         ⇒ (r + 1) or (6r - 3) = 0

         r + 1 = 0     or 6r - 3 = 0

         r = - 1      or      6r = 3

         r = - 1      or   r = 1/2

Thus, the solutions to the equation are; r = - 1 or r = 1/2 since erx is never 0.

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