Answer:
Mass = 73.73 g
Explanation:
Given data:
Mass of Mg used = 24.48 g
Mass of HCl used = ?
Mass of hydrogen gas produced = 2.04 g
Mass of Magnesium chloride produced = 96.90 g
Solution:
Chemical equation:
Mg + 2HCl → MgCl₂ + H₂
Number of moles of Mg:
Number of moles = mass/ molar mass
Number of moles = 24.48 g/ 24.305 g/mol
Number of moles = 1.01 mol
Now we will compare the moles of Mg with HCl from balance chemical equation.
Mg : HCl
1 ; 2
1.01 : 2/1× 1.01 = 2.02 mol
Mass of HCl react:
Mass = number of moles × molar mass
Mass = 2.02 × 36.5 g/mol
Mass = 73.73 g
Magnesium (24.48g) reacts with hydrochloric acid (74.46 g) to produce hydrogen gas (2.04g) and magnesium chloride (96.90g).
Let's consider the following balanced equation.
[tex]Mg + 2 HCl \rightarrow H_2 + MgCl_2[/tex]
24.48 g of magnesium react with an unknown mass of hydrochloric acid to produce 2.04 g of hydogen gas and 96.90 g of magnesium chloride.
According to Lavoisier's law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. As a consequence, the sum of the masses of the reactants must be equal to the sum of the masses of the products.
[tex]mMg + mHCl = mH_2 + mMgCl_2\\mHCl = mH_2 + mMgCl_2 - mMg\\mHCl = 2.04 g + 96.90 g - 24.48 g = 74.46 g[/tex]
Magnesium (24.48g) reacts with hydrochloric acid (74.46 g) to produce hydrogen gas (2.04g) and magnesium chloride (96.90g).
You can learn more about Lavoisier's law here: https://brainly.com/question/11429078
