Answer:
[tex]q=3.19*10^{-8}C[/tex]
Explanation:
The expression for the electric force between two charges
[tex]F=k\frac{q_1q_2}{r^2}\\[/tex]
where K is the Coulomb's constant (k=9*10^{9}Nm^2/C^2), and we have that
q1=q
q2=3q
r=3.39m
F=2.4*10^{-6}N
By replacing in the formula we have
[tex]F=2.4*10^{-6}N=(9*10^{9}\frac{Nm^2}{C^2})\frac{(q)(3q)}{(3.39m)^2}\\\\[/tex]
and by taking apart q we have
[tex]q=3.19*10^{-8}C[/tex]
hope this helps!!
