Answer:
Mole fraction of LiCl = 0.4
Explanation:
Given data:
Mass of NaCl = 0.564 g
Mass of KCl = 1.52 g
Mass of LiCl = 0.857 g
Mole friction of LiCl = ?
Solution:
First of all we will calculate the moles of each compound.
Moles of NaCl:
Moles of NaCl = mass/ molar mass
Moles of NaCl = 0.564 g/ 58.44 g/mol
Moles of NaCl = 0.01 mol
Moles of KCl:
Moles of KCl = mass/ molar mass
Moles of KCl = 1.52 g/ 74.55 g/mol
Moles of KCl = 0.02 mol
Moles of LiCl:
Moles of LiCl = mass/ molar mass
Moles of LiCl = 0.857 g/ 42.39 g/mol
Moles of LiCl = 0.02 mol
Mole fraction of LiCl:
Mole fraction of LiCl = moles of LiCl / total moles of mixture
Total number of moles = 0.02+0.02+0.01 = 0.05
Mole fraction of LiCl = 0.02/0.05 = 0.4
