Answer:
The height of the building is H = 360.44 m
Step-by-step explanation:
From the Δ ABC
AB = x
CD = BE = 250 m
BC = DE = 158 m
Height of the building H = AB + BC = x + 158 ------ (1)
In the Δ ABC
[tex]\tan 39 = \frac{AB}{BE}[/tex]
[tex]0.809 = \frac{x}{250}[/tex]
x = 202.44 m
Put this value of x in equation (1) we get
Height of the building H = 202.44 + 158
H = 360.44 m
Therefore the height of the building is H = 360.44 m
