batman12272003
contestada

A circular above ground pool has a height of 52 inches, and a volume of 1100 ft^3. What is the radius of the pool to the nearest tenth of a foot? Use the equation V=pi*r^2*h.
(V= volume, r= radius, and h=height)

Respuesta :

wegnerkolmp2741o

Answer:

9 ft

Step-by-step explanation:

The pool is in the shape of a cylinder

V = pi r^2h

We need to change the height from inches to ft

52 inches * 1ft/12 inches = 13/3 ft

1100 =pi * r^2 *13/3

Multiply each side by 3

3300 = pi * r^2 *13/3 *3

3300 = pi * r^2 *13

Divide each side by 13pi

3300/13pi = pi * r^2 *13/13pi

3300/ (13*3.14) = r^2

80.84272415 = r^2

Take the square root of each side

sqrt(80.84272415) =sqrt( r^2)

8.991258208 =r

To the nearest foot

9 =r

amna04352

Answer:

9.0 ft

Step-by-step explanation:

Height = 52/12 ft = 13/3 ft

1100 = 3.14 × r² × 13/3

r² = 80.84272415

r = 8.991258208

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