Answer:
2.7x10⁻⁸ N/m²
Explanation:
Since the piece of cardboard absorbs totally the light, the radiation pressure can be found using the following equation:
[tex] p_{rad} = \frac{I}{c} [/tex]
Where:
[tex] p_{rad}[/tex]: is the radiation pressure
I: is the intensity of the light = 8.1 W/m²
c: is the speed of light = 3.00x10⁸ m/s
Hence, the radiation pressure is:
[tex] p_{rad} = \frac{I}{c} = \frac{8.1 W/m^{2}}{3.00 \cdot 10^{8} m/s} = 2.7 \cdot 10^{-8} N/m^{2} [/tex]
Therefore, the radiation pressure that is produced on the cardboard by the light is 2.7x10⁻⁸ N/m².
I hope it helps you!
Answer:
The answer is 2.7x10⁻⁸ Pa
Explanation:
The expression for total absorption is:
Pr = I/c
Where I = intensity of light
c = velocity of light
Replacing:
Pr = 8.1/3x10⁸ = 2.7x10⁻⁸ Pa
