The ratio of the length to the width to the height of a rectangular box is 12:4:7. The sum of the length and the width is 32 inches. Find the surface area of the box.

Respuesta :

Answer:

The surface area of the box is [tex]1280 sq. inches[/tex].

Step-by-step explanation:

Given that,

Ratio of the length to the width to the height of a rectangular box is [tex]12:4:7.[/tex]

The sum of the length and width of box is [tex]32.[/tex]

From the question,

Dimension of Rectangular box are [tex]Length (l),\ Width (w) , Height (h)[/tex].

  Let the side of rectangular box is x.

                          [tex]length = 12x\\\\width = 4x\\\\Height = 7x[/tex]  

Now,   Sum of length and width is [tex]32[/tex][tex]inches[/tex]

 Then,                [tex]12x+4x=32[/tex]

      ⇒                         [tex]16x=32[/tex]

      ⇒                            [tex]x=\frac{32}{2} = 2\\[/tex]

Here we get the dimensions are,

                        [tex]length = 12x=24inches\\width = 4x=8inches\\Height = 7x=14inches[/tex]

Then,  surface Area of rectangular box = [tex]2(lw+wl+ hl)[/tex]

                                                                 = [tex]2(24\times8+8\times14+24\times14)[/tex]

                                                                 = [tex]2(192+112+336) =2\times640[/tex]

                                                                 = [tex]1280 sq. inches[/tex]

Hence,

The surface area of the box is [tex]1280 sq. inches[/tex].