A rectangle has a perimeter 204 it’s length six feet longer than twice it’s width if L stands for the rectangle and W stands for its width, write a system of equations that models the information given in this problem and solve it to find the length and width of this rectangle.

Respuesta :

Answer:

W=32

L=70

Step-by-step explanation:

L=2w+6

204=2L+2W

204=2w+2(2w+6)

204=2w+4w+12

192=6w

w=32

L=2(32)+6

L=70