What are the center and radius of the circle with equation (−)+(−)=?Open x minus 4 close squared . Plus . Open y minus 9 close squared . Equals , 1 question mark

Respuesta :

Answer:

Center and radius of the circle of the  equation  [tex]{(x - 4)^{2} + (y - 9)^{2} = 1[/tex]

center = ( 4,9)         Radius = 1

Step-by-step explanation:

Given -

Equation of circle is  [tex](x - 4)^{2} + (y - 9)^{2} = 1[/tex]

The equation of circle is  represented by

   [tex]\boldsymbol{\mathbf{(x - a)^{2} + (y - b)^{2} = r^{2}}}[/tex]

where a and b are center of circle and radius r

Comparing these equation

then a = 4  and b = 9    and r = 1