Answer:
We suppose that the 250 legos are different between them, so we have that:
for 1 lego, we have 250 combinations.
For two legos, we have 250 for the first lego, and 249 for the second lego, this is 250*249 combinations.
for 3 legos, we will have 250*249*248 probabilities.
and so on:
Then the total number of combinations will be:
C = 250 + 250*249 + 250*249*248 + ....
= 250*(1 + 249*(1 + 248*(1 + 247*(......))))
The number that is kinda hard to calculate, even in a calculator
this summation can be written as:
∑(250)!/(249 - n)!
wich is a big big big number
