Respuesta :

Answer:

Step-by-step explanation:

assuming it is [tex]x^{2} +8x+4[/tex]

Using Quadratic formular -

a - 1

b - 8

c - 4

[tex]x= \frac{ -8 -,+ \sqrt{(8^2) - 4 (1)(4)}}{2(1)} \\\\[/tex]

[tex]x = \frac{-8 +,- \sqrt{48} }{2}\\\\[/tex]

[tex]x = \frac{-8+,- 4\sqrt{3} }{2}[/tex]

[tex]x = {-4+,- 2\sqrt{3} }[/tex]

Answer:

x = –4 ± 2[tex]\sqrt{3}[/tex]

Step-by-step explanation: