Answer:
208.7°C was the initial temperature of the limestone.
Explanation:
Heat lost by limestone will be equal to heat gained by the water
[tex]-Q_1=Q_2[/tex]
Mass of limestone = [tex]m_1=62.6 g[/tex]
Specific heat capacity of limestone = [tex]c_1=0.921 J/g^oC [/tex]
Initial temperature of the limestone = [tex]T_1=?[/tex]
Final temperature = [tex]T_2[/tex]=T = 51.9°C
[tex]Q_1=m_1c_1\times (T-T_1)[/tex]
Mass of water= [tex]m_2=75.0 g[/tex]
Specific heat capacity of water= [tex]c_2=4.186 J/g^oC [/tex]
Initial temperature of the water = [tex]T_3=23.1^oC[/tex]
Final temperature of water = [tex]T_2[/tex]=T = 51.9°C
[tex]Q_2=m_2c_2\times (T-T_3)[/tex]
[tex]-Q_1=Q_2[/tex]
[tex]-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)[/tex]
On substituting all values:
[tex]-(62.6 g\times 0.921 J/g^oC\times (51.9^oC-T_1))=75.0 g\times 4.186 J/g^oC\times (51.9^oC-23.1^oC)[/tex]
[tex]T_1=208.7^oC[/tex]
208.7°C was the initial temperature of the limestone.
