briangarcia0181
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In a ballistics test, a 52g bullet hits a sand bag and stops after moving 1.34 m. If the initial bullat
velocity was 55 m/s what was the magnitude of the average force of friction. ​

Respuesta :

Answer:

Friction force on the bullet is 58.7 N opposite to its velocity

Explanation:

As we know that initial speed of the bullet is 55 m/s

after travelling into the sand bag by distance d = 1.34 m it comes to rest

so final speed

[tex]v_f = 0[/tex]

now we can use kinematics top find the acceleration of the bullet

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

so we have

[tex]0 - 55^2 = 2(a)(1.34)[/tex]

[tex]a = -1128.7 m/s^2[/tex]

now by Newton's II law we know that

[tex]F = ma[/tex]

so we have

[tex]F = (0.052)(-1128.7)[/tex]

[tex]F = -58.7 N[/tex]

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