Answer:
[tex]\mu=10\\\\\sigma=2.828[/tex]
Step-by-step explanation:
-This is a binomial probability function.
-Given that the probability of success is p=0.2 and the sample size, n=50.
-The mean is calculated using the formula:
[tex]\mu=np\\\\=50\times 0.2\\\\=10[/tex]
-We then calculate the standard deviation as:
[tex]\sigma=\sqrt{npq}, \ \ q=1-p\\\\=\sqrt{50\times 0.2(1-0.2)}\\\\=2.828[/tex]
Hence, the mean is 10 ad the standard deviation is 2.828
