Answer:
grams O₂(g) ≅ 15.9 g O₂(g) (3 sig. figs.)
Explanation:
2Cu + O₂ => 2CuO
Convert given to moles, solve by equation rxn ratio then convert to grams.
Moles CuO formed = 81.0 g / 81.5 g·mol⁻¹ = 0.994 mol CuO
0.994 mol CuO requires 0.994 mol Cu = 0.994 mol Cu x 64 g·mol⁻¹ = 63.6 g Cu => from this, the amount of O₂ needed = 1/2(0.994 mol) O₂(g) = 0.497 mol O₂(g) = (0.497 mol O₂(g))(32 g·mol⁻¹) = 15.904 g O₂(g) ≅ 15.9 g O₂(g) (3 sig. figs.)
