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Calculate the concentration of hydrochloric acid if 50.0 mL of hydrochloric acid is neutralized by 25.0 mL of 2.0 M sodium hydroxide.
HCl (aq) + NaOH (aq) → H2O (l) + NaCl (aq)

Respuesta :

Answer:

1.0 M is the concentration of hydrochloric acid.

Explanation:

[tex]HCl (aq) + NaOH (aq) \rightarrow H_2O (l) + NaCl (aq)[/tex]

To calculate the concentration of acid, we use the equation given by neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]HCl[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.

We are given:

[tex]n_1=1\\M_1=?\\V_1=50.0 mL\\n_2=1\\M_2=2.0 M\\V_2=25.0 mL[/tex]

Putting values in above equation, we get:

[tex]1\times M_1\times 50.0 mL=1\times 2.0 M\times 25.0 mL[/tex]

[tex]M_1=\frac{1\times 2.0 M\times 25 mL}{1\times 50.0 mL}=1.0M[/tex]

1.0 M is the concentration of hydrochloric acid.