Answer:
It is 2/121.
Step-by-step explanation:
For the first draw, the probability of picking P is 1/11 since there is only one P letter in the 11 letters. If we replace the P after drawing, then for the second draw, the probability of drawing I is 2/11 since there are 2 I's in the 11 letters.
Since the events are seperate, the probability of picking P and then picking I is (1/11)x(2/11) = 2/121.
I hope this answer helps.
