Answer:
True
Step-by-step explanation:
Even though we cannot see the parallelogram, we can assume the dimensions of the original parallelogram is height= 3 and base= 6.
If we double the dimensions, we get:
height=6 band base=12.
The area of the original parallelogram is 18 square units.
The area of the enlarged parallelogram is 6×12= 72 square units.
Now,
[tex] \frac{72}{18} = 4[/tex]
Hence, the area of the larger parallelogram is 4 times more than the original.
