Segment AB has endpoints at A  4, 8 and B10,13 . If point P lies on AB such that AP BP : 2 : 5  , then find the coordinates of P. Show all your work.

Respuesta :

Answer:

Hence, the coordinate of point P is [tex](\frac{40}{7}, \frac{66}{7})[/tex].

Step-by-step explanation:

Given that,

AB is the line segment having endpoints are A and B.

Coordinate of point A is [tex](4, 8)[/tex] and coordinate of point B is [tex](10, 13)[/tex].

Point P lies on line segment AB which divides the line segment AB in the 2:5.

Let, the coordinate of point P which divides the line segment AB is [tex](x, y)[/tex].

Now,

The coordinate of a point P, which divides the line segment AB internally in the ratio [tex]m_{1} :m_{2}[/tex] are given by:

                                    [tex]\frac{m_{1}x_{2}+m_{2}x_{1} }{m_{1}+m_{2} } , \frac{m_{1}y_{2}+m_{2}y_{1} }{m_{1}+m_{2} }[/tex]

[tex]x[/tex] coordinate of point P is [tex]\frac{2\times 10+5\times 4}{2+5} =\frac{20+20}{7}=\frac{40}{7}[/tex]

[tex]y[/tex] coordinate of point P is [tex]\frac{2\times 13+5\times 8}{2+5} =\frac{26+40}{7} =\frac{66}{7}[/tex]

Hence, the coordinate of point P is [tex](\frac{40}{7}, \frac{66}{7})[/tex].

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