Answer:
1000 N
Explanation:
The magnitude of the electrostatic force between two charged object is given by
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb constant
q1, q2 is the magnitude of the two charges
r is the distance between the two objects
Moreover, the force is:
- Attractive if the two forces have opposite sign
- Repulsive if the two forces have same sign
In this problem:
[tex]q_1=q_2=+1C[/tex] are the two charges
r = 3000 m is their separation
Therefore, the electric force between the charges is:
[tex]F=(9\cdot 10^9)\frac{(1)(1)}{3000^2}=1000 N[/tex]
