Answer: hamburger $3.00
Coke $1.50
Step-by-step explanation:
2hamburgers & 3cokes= $10.50
4hamburgers & 4cokes= $18.00
Let hamburger represent H
And coke represent C
2H +3C= 10.50.......equation 1
4H+4C= 18.00.......equation 2
2H =10.50 -3C...........equation 3
The 4H can be rewriting as
2(2H) right
So substitute for the 4H
So we have,
2(2H) +4C= 18
Substitute for 2H
2(10.50 -3C) +4C =18
Open the bracket
21 -6C +4C= 18
21-2C= 18
-2C = 18-21
-2C = -3
Minus cancel minus
C= 3/2 = $1.5
Substitute for c in equation 1
2H+3C =10.50
2H+3(1.5)= 10.50
2H+4.5=10.5
2H= 10.5-4.5
2H =6
H= 6/2
H=$3
So
An hamburger cost $3.00
A coke cost $1.50
