Answer:
The force between the two charges will be 13.22N.
Explanation:
The force between the two charges is given by Coulombs law which says
[tex]F = k\dfrac{Q_1Q_2}{R^2}.[/tex]
In our case
[tex]Q_1= 0.00045C[/tex],
[tex]Q_2 = 0.0000032C[/tex],
[tex]R = 0.99m[/tex].
therefore,
[tex]F = (9*10^9)\dfrac{(0.00045C)(0.0000032C)}{(0.99m)^2}.[/tex]
[tex]\boxed{F=13.22N}[/tex]
Hence, the force between the two charges will be 13.22N.
