There are 45 numbers out of which 5 numbers are required to win an enormous sum of money
No of ways in which 5 numbers can be selected out of 45 numbers.
[tex]C_{45}^5=\frac{45!}{40!5!} =1221759[/tex]
out of which there is only combination foe contest winning
[tex]P=\frac{1}{1221759}[/tex]
When 100 different tickets are bought then
Probability of winning: [tex]\frac{100}{1221759}[/tex]
Probably of winning≈0,000082
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P.S. Hello from Russia :^)
