Answer:
8L will be the new volume
Explanation:
Let's use the Ideal Gases Law to determine the answer of this question:
Pressure . volume = number of moles . R . T
P . V = n . R . T
We can propose the two situation for the gas:
P₁ . V₁ = n₁ . R . T₁
P₂ . V₂ = n₁ . R . T₂
Notice that R is a constant and n₁ (moles of gas), is not modified with the changes, so we can cancel them.
For the second situation: P₂ = P₁/8 and T₂ = T₁/9
(P₁ . 9L) / T₁ = (P₁/8 . V₂) / T₁/9
(P₁ . 9L) / T₁ . T₁/9 = (P₁/8 . V₂)
P₁ . 1L = P₁/8 . V₂
P₁ . 1L . 8/P₁ = V₂ → 8L
You can also see it, if you put numbers, for example
1 mol of the gas at 1 atm, let's find out the temperature:
1 atm . 9L = 1 mol . 0.082 . T
9/ 0.082 = 110 K
Second situation: 1/8 atm . V = 1 mol . 0.082 . 110/9 K
V = (1 mol . 0.082 . 110/9 K) . 8 atm → 8.02 L ≅ 8L
