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The heat of combustion of propane, C3H8, is 2220 kJ/mol. The specific heat of copper is 0.385 J/g°C. How many grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C, assuming none of the heat is lost to the surroundings?

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yureisyreyes03

Answer:

Explanation:

q = (mass) (temp change) (specific heat)

q = (10000 g) (40 °C) (0.385 J/g⋅°C) = 154000 J = 154 kJ

154 kJ / 2220 kJ/mol = 0.069369369 mol

0.069369369 mol times 44.0962 g/mol = 3.06 g (to three sig figs)

answer choice 4

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