Answer:
0.85
Step-by-step explanation:
Given two events A and B, the probability that either A or B occurs is given by:
[tex]p(A\cup B) = p(A)+p(B)-p(A\cap B)[/tex]
where
[tex]p(A)[/tex] the probability that A occurs
[tex]p(B)[/tex] is the probability that B occurs
[tex]p(A\cap B)[/tex] is the probability that both A and B occur at the same time
In this problem, we know the following facts:
[tex]p(o) = 0.83[/tex] is the probability that the car requires an oil change
[tex]p(b)=0.17[/tex] is the probability that the car requires a brake repair
[tex]p(o\cap b) = 0.15[/tex] is the probability that the car requires both an oil change and brake repair
Therefore, the probability that either o (car requiring oil change) or b (car requiring brake repait) occur is:
[tex]p(o\cup b)=p(o)+p(b)-p(o\cap b)=0.83+0.17-0.15 = 0.85[/tex]
