9.49 grams of Ag is produced in the reaction if 6.50X1023 atoms
of magnesium (Mg) react.
Explanation:
Balanced chemical reaction:
2 AgNO3 (s) + 1 Mg(s) 3 Mg(NO3)2 (s) + 2 Ag (s
data given:
6.50X1023 atoms of magnesium (Mg) react.
then amount of Ag formed =?
We know that 6.022 x [tex]10^{23}[/tex] atoms are present in 1 gram/ mole of a substance
so 6.50X1023 will have x grams
so, 1.07 grams of Mg will react to form x grams of Ag
atomic mass of Mg 24.30
number of moles of Mg = [tex]\frac{1.07}{24.30}[/tex]
= 0.044 moles of Mg
1 mole of Mg reacts to give 2 moles of Ag
0.044 moles of Mg reacts to give x moles of Ag
[tex]\frac{2}{1}[/tex] = [tex]\frac{x}{0.044}[/tex]
x = 0.088 moles of Ag is formed (atomic mass of silver 107.86g/mole)
mass = atomic mass X number of moles
= 107.86 x 0.088
= 9.49 grams of Ag is formed.
