A plate of glass with parallel faces having a refractive index of 1.57 is resting on the surface of water in a tank. A ray of light coming from above in air makes an angle of incidence 37.5 ∘ with the normal to the top surface of the glass.

Respuesta :

θ₃ is 27.12°

Explanation:

Using Snell's law:

n₁ sin θ₁ = n₂ sin θ₂

where,

n₁ = refractive index of material with incident light

n₂ = refractive index of material with refracted light

(a)

1 → air

2 → glas

3 → water

n(water) = n₃ = 1.333

From air to glass,

n₁ sin θ₁ = n₂sin θ₂

The angle of refraction 2 is the angle of incidence when the light comes from glass to water.

From glass to water:

n₁ sin θ₁ = n₃ sin θ₃

1 X sin 37.5° = 1.333 sin θ₃

sin θ₃ =  sin (37.5)/ 1.333

sin θ₃ = 0.456

θ₃ = 27.12°

Therefore, θ₃ is 27.12°