Answer: 0.01 m/s2
Explanation:
Given that:
Velocity of supertanker = 7.2 m/s (about 12 mph)
Time taken = 12 min
(Since the SI unit of time is seconds, convert 12 minutes to seconds
1 minute = 60 seconds
12 minutes = 12 x 60 = 720 seconds)
Average deceleration = ?
Recall that deceleration is obtained by dividing velocity by time taken.
i.e Deceleration = velocity / time
Deceleration = 7.2 m/s / 720 seconds
= 0.01 m/s2
Thus, the magnitude of its average deceleration is 0.01 meters per second squared.
