Her average weekly income in August was $200.
Step-by-step explanation:
To find the income in july :
Given that,
Let,
'x' be the 100% of income she got in July.
Therefore, the income $207 in September is 115% of x.
⇒ 115% of x = 207
⇒ 1.15 × x = 207
⇒ x = 207 / 1.15
⇒ x = 180
∴ Her average weekly income in July was $180.
To find the income in August :
Given that,
Let,
'y' be the 100% of income she got in August.
Therefore, the income $180 in July is 90% of y.
⇒ 90% of y = 180
⇒ 0.9 × y = 180
⇒ y = 180/0.9
⇒ y = 200
∴ Her average weekly income in August was $200.
her average weekly income in August was $200 .
Step-by-step explanation:
Let in July income was x , So in September :
⇒ [tex]x+\frac{15x}{100}[/tex]
According to question , her average weekly income in September was $207 i.e.
⇒ [tex]x+\frac{15x}{100}=207[/tex]
⇒ [tex]\frac{115x}{100}=207[/tex]
⇒ [tex]x=207(\frac{100}{115})[/tex]
⇒ [tex]x=180[/tex]
Now , average weekly income in July was 10% less than it was in August , let income of august = y, i.e.
Income in august = [tex]180+\frac{August(10)}{100}[/tex]
⇒ [tex]y=180 + \frac{y(10)}{100}[/tex]
⇒ [tex]\frac{9}{10}y=180[/tex]
⇒ [tex]y=\$200[/tex]
Therefore , her average weekly income in August was $200 .
