Answer: 313.24K
Explanation:
Given that:
Initial air pressure P1 = 210kPa
Initial Temperature T1 = 26°C
(Since, the SI unit of temperature is Kelvin, convert temperature in celsius to kelvin
26°C + 273 = 299K)
Final temperature T2 = ?
Final pressure P2 = 220kPa
Since, pressure and temperature are involved while volume is constant, apply the formula for pressure law
P1/T1 = P2/T2
210kPa/299K = 220kPa/T2
Cross multiply
210kPa x T2 = 220kPa x 299K
210 x T2 = 65780
T2 = (65780/210)
T2 = 313.24K
Thus, the temperature of the air in the tyre is 313.24K
