Answer:
final temperature T = 24.84ºC
Explanation:
given data
copper volume = 1 L
temperature t1 = 500ºC
oil volume = 200 L
temperature t2 = 20ºC
solution
Density of copper [tex]\rho[/tex] cu = 8940 Kg/m³
Density of light oil [tex]\rho[/tex] oil = 889 Kg/m³
Specific heat capacity of copper Cv = 0.384 KJ/Kg.K
Specific heat capacity of light oil Cv = 1.880 KJ/kg.K
so fist we get here mass of oil and copper that is
mass = density × volume ................1
mass of copper = 8940 × 1 × [tex]10^{-3}[/tex] = 8.94 kg
mass of oil = 889 × 200 × [tex]10^{-3}[/tex] = 177.8 kg
so we apply here now energy balance equation that is
[tex]M(cu)\times Cv \times (T-T1)_{cu} + M(oil) \times Cv\times (T-T2)_{oil}[/tex] = 0
put here value and we get T2
[tex]8.94\times 0.384 \times (T-500) + 177.8 \times 1.890\times (T-20)[/tex] = 0
solve it we get
T = 24.84ºC
