Answer: P < 300 = 0.102
Step-by-step explanation:
Suppose the round-trip airfare between Boston and Orlando follows the normal probability distribution, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the round-trip airfare between Boston and Orlando.
µ = mean
σ = standard deviation
From the information given,
µ = $387.20
σ = $68.50
The probability that a randomly selected airfare between Boston and San Francisco will be less than $300 is expressed as
P < 300
For x = 300,
z = (300 - 387.20)/68.5 = - 1.27
Looking at the normal distribution table, the probability corresponding to the z score is 0.102
