Answer:
3 ft by 4/3 feet.
Step-by-step explanation:
We have been given that a card is 9 inches by 4 inches. A printing shop will enlarge it so that the longer side is any lengths up to 3 ft. We are asked to find the dimensions of biggest enlargement.
We will use proportions to solve our given problem.
[tex]\frac{\text{Card width}}{\text{Card length}}=\frac{\text{Enlarged width}}{\text{Enlarged length}}[/tex]
Upon substituting our given values, we will get:
[tex]\frac{\text{4 inches}}{9 \text{ inches}}=\frac{\text{Enlarged width}}{\text{3 ft}}[/tex]
[tex]\frac{4}{9}=\frac{\text{Enlarged width}}{\text{3 ft}}[/tex]
[tex]\frac{4}{9}\times \text{3 ft}=\frac{\text{Enlarged width}}{\text{3 ft}}\times \text{3 ft}[/tex]
[tex]\frac{4}{3}\times \text{ft}=\text{Enlarged width}[/tex]
Therefore, the dimensions of the biggest enlargement would be 3 ft by 4/3 feet.
