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A flatbed truck is supported by its four drive wheels, and is moving with an acceleration of 6.3 m/s2. For what value of the coefficient of static friction between the truck bed and a cabinet will the cabinet slip along the bed surface?

Respuesta :

Answer:

Coefficient of static friction will be equal to 0.642  

Explanation:

We have given acceleration [tex]a=6.3m/sec^2[/tex]

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

We have to find the coefficient of static friction between truck and a cabinet will

We know that acceleration is equal to [tex]a=\mu g[/tex], here [tex]\mu[/tex] is coefficient of static friction and g is acceleration due to gravity

So [tex]\mu =\frac{a}{g}=\frac{6.3}{9.8}=0.642[/tex]

So coefficient of static friction will be equal to 0.642

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