Use the following to answer question 39: The average score of 100 students taking a statistics final was 70 with a standard deviation of 7. Assuming a normal distribution, what is the probability that students scored less than 60

Respuesta :

Answer:

The probability of students scored less than 60 = .0768

Step-by-step explanation:

Given -

Mean score [tex](\nu )[/tex] = 70

standard deviation [tex](\sigma )[/tex] = 7

Let X be the score of students

the probability that students scored less than 60 =

[tex]P(X< 60)[/tex]  = [tex]P(\frac{X - \nu }{\sigma}< \frac{60 - 70}{7})[/tex]

                  =  [tex]P(z < \frac{60 - 70}{7})[/tex]   put[ Z= [tex]\frac{X - \nu }{\sigma}[/tex]]

                   =  [tex]P(z < -1.428)[/tex]  using z table

                    =  .0768