Answer:
111.5 grams of lead (II) oxide would be produced.
Explanation:
[tex]2PbS+3O_2\rightarrow 2PbO+2SO_2[/tex]
Moles of oxygen = 0.750 mol
According to reaction, 3 moles of oxygen gas gives 2 moles of lead(II) oxide ,then 0.750 moles of oxygen gas will give:
[tex]\frac{2}{3}\times 0.750 mol=0.50 mol[/tex] of lead (II) oxide
Mass of 0.50 moles lead(II) oxide:
0.50 mol × 223 g/mol = 111.5 g
111.5 grams of lead (II) oxide would be produced.
