Answer:
Average induced emf will be equal to 0.00156 volt
Explanation:
We have given diameter of the wire d = 16.1 cm
So radius [tex]r=\frac{16.1}{2}=8.05cm=0.08m[/tex]
Cross sectional area of the wire [tex]A=\pi r^2=3.14\times 0.08^2=0.02m^2[/tex]
Magnetic field is changing from 0.53 T to 0.19 T
So change in magnetic field dB = 0.19-0.53 = -0.34 T
Time taken to change in magnetic field dt = 0.23 sec
Induced emf is given by [tex]e=\frac{-d\Phi }{dt}=-A\frac{dB}{dt}=-0.02\times \frac{0.34}{0.23}=0.00156volt[/tex]
So average induced emf will be equal to 0.00156 volt
