f the angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of the tree, what is the height of the tree (to the nearest tenth of a foot)?
A) 14.0 feet
B) 16.9 feet
C) 19.3 feet
D) 20.7 feet

Respuesta :

Given:

The angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of the tree.

We need to determine the height of the tree.

Height of the tree:

Let the height of the tree be h.

The height of the tree can be determined using the trigonometric ratio.

Thus, we have;

[tex]tan \ \theta=\frac{opp}{adj}[/tex]

Substituting the values, we get;

[tex]tan \ 34^{\circ}=\frac{h}{25}[/tex]

Multiplying both sides by 25, we have;

[tex]tan \ 34^{\circ} \times 25=h[/tex]

 [tex]0.6745 \times 25=h[/tex]

       [tex]16.8625=h[/tex]

Rounding off to the nearest tenth of a foot, we get;

[tex]16.9=h[/tex]

Thus, the height of the tree is 16.9 feet.

Hence, Option B is the correct answer.

Answer:

16.9 feet

Step-by-step explanation: