Answer:
[tex]0.082 atm L mol^{-1} K^{-1}[/tex]
Explanation:
The pressure, the volume and the temperature of an ideal gas are related to each other by the equation of state:
[tex]pV=nRT[/tex]
where
p is the pressure of the gas
V is the volume of the gas
n is the number of moles
R is the gas constant
T is the absolute temperature
For the gas in this problem:
n = 2.00 mol is the number of moles
V = 17.4 L is the gas volume
p = 3.00 atm is the gas pressure
[tex]T=45C+273=318 K[/tex] is the absolute temperature
Solving for R, we find the gas constant:
[tex]R=\frac{pV}{nT}=\frac{(3.00)(17.4)}{(2.00)(318)}=0.082 atm L mol^{-1} K^{-1}[/tex]
