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If a 200 turn, 10-3 m2 cross-sectional area coil is immersed in a magnetic field such that the plane of the coil is perpendicular to the field. If the magnetic field increases by 6 T/s, then how much voltage is induced

Respuesta :

Answer:

1.2 volt induced in coil.

Explanation:

Given:

Number of turns [tex]N = 200[/tex]

Cross sectional area [tex]A = 10^{-3}[/tex] [tex]m^{2}[/tex]

Rate of increasing magnetic field [tex]\frac{dB}{dt} = 6[/tex] [tex]\frac{T}{s}[/tex]

From the faraday's law,

Induced emf is given by,

   [tex]\epsilon = -N\frac{d \phi}{dt }[/tex]

Where [tex]\phi =[/tex] magnetic flux

  [tex]\phi = AdB \cos(0)[/tex]          ( because angle between normal coil and field is zero)

Where [tex]A =[/tex] area of coil

Put the value of [tex]\phi[/tex] in above equation,

Here we neglect minus sign

   [tex]\epsilon = NA\frac{dB}{dt}[/tex]

   [tex]\epsilon = 200 \times 10^{-3} \times 6[/tex]

   [tex]\epsilon = 1.2[/tex] V

Therefore, 1.2 volt induced in coil

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