Answer:
The weight of aspirin lost is [tex]W =0.03267(V_A +V_B) N[/tex]
The percent yield is lowered by [tex]A = \frac{Amount \ of \ aspirin \ obtained - Lost Amount }{Expected\ Amount\ of \ Aspirin } *\frac{100}{1}[/tex]
Explanation:
From the question we are told that
Since the solubility of aspirin in water is 1 g per 300 mL it implies that after crystallization the solution would contain 1 g for every 300mL of water at 25°
Let assume that the volume of the solution is [tex]V_A[/tex]
The the aspirin lost after filtration would be
[tex]= \frac{1}{300} * V_A[/tex]
[tex]=\frac{V_A}{300}g[/tex]
Let assume that you used water of volume [tex]V_B[/tex] to wash the crystallized aspirin then the lost during washing would be
[tex]= \frac{1}{300} * V_B[/tex]
[tex]= \frac{V_B}{300}[/tex]
So the total loss is
[tex]= \frac{V_A}{300} + \frac{V_B}{300}[/tex]
[tex]\frac{V_A +V_B}{300}g[/tex]
So the weight of aspirin lost denoted by W is
[tex]W = \frac{V_A +V_B}{300} *9.8[/tex]
[tex]W =0.03267(V_A +V_B) N[/tex]
Let denote How much was your percent yield lowered by this loss by A
So
[tex]A = \frac{Amount \ of \ aspirin \ obtained - Lost Amount }{Expected\ Amount\ of \ Aspirin } *\frac{100}{1}[/tex]
