A right triangular pyramid has a height of 10 inches and a base area of 41.57 square inches. What is the volume, in cubic inches, of the pyramid?

Respuesta :

Volume of a pyramid is (base^2) times (height/3). (41.57^2) times (10/3) Answer is approximately 5760.22 inches cubed.

The volume of the rectangular pyramid with the given values of height and base area is 138.5 cubic inches.

What is a right triangular pyramid?

A right triangular pyramid is simply a triangular pyramid which has an equilateral base, and whose top is directly above the base's centroid.

The volume of right triangular pyramid is expressed as;

V = 1/3 × b² × h

where b is the length of the base and h is the perpendicular height.

Given the data in the question;

  • Height of the pyramid h = 10in
  • Base area A = 41.57in²

First we find the dimension of the base length.

Since area square is A = b².

Hence;

41.57in² = b²

b = √41.57in²

b = 6.447in

Now, we substitute our values into the expression above.

V = 1/3 × b² × h

V = 1/3 × (6.447in)² × 10in

V = 1/3 × 41.563809in² × 10in

V = 138.5in³

Therefore, the volume of the rectangular pyramid with the given values of height and base area is 138.5 cubic inches.

Learn more about volume of pyramids here: https://brainly.com/question/21308574

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