Answer:
The torque applied to the nut is 34.6 N-m.
Explanation:
Given that,
Length of the wrench, l = 0.5 m
Force applied by the wrench, F = 80 N
The force must be exerted upward and at an angle of 60.0 degrees, with respect to a line from the bolt through the end of the wrench.
Torque applied to the nut is given by :
[tex]\tau=Fr\ \sin\theta\\\tau=80\times 0.5\ \sin(60)\\\tau=34.6\ N.m[/tex]
So, the torque applied to the nut is 34.6 N-m.
