(1 point) A computer retail store has 8 personal computers in stock. A buyer wants to purchase 4 of them. Unknown to either the retail store or the buyer, 4 of the computers in stock have defective hard drives. Assume that the computers are selected at random. (a) In how many different ways can the 4 computers be chosen

Respuesta :

Answer:

Total no  of different ways can the 4 computers be chosen  = 70

Step-by-step explanation:

Given -

A computer retail store has 8 personal computers in stock.A buyer wants to purchase 4 of them.

(Using the combination formula)

The combination of n events taking r at a time = [tex]\mathbf{\binom{n}{r}}[/tex]

where n = 8 and r = 4

Total no  of different ways can the 4 computers be chosen = [tex]\mathbf{\binom{8}{4}}[/tex]

    =  [tex]\boldsymbol{\frac{8!}{(4!)(4!)}}[/tex]

=   70

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