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A 1 phase load operates at 600 V and consumes 75 kW with a 0.85 lagging power factor. Compute the complex power consumed by the load. Type the answer with two decimal digits. The answer is in VA units.

Respuesta :

Answer:

Complex power=84 W

Explanation:

using equation

s=vs^2/2z

s=600^2/2z

s=84+29.4j

using s=P+jq

complex power=P=84 W

Geophilip

Answer:

Complex power (s) = 88235.3costheta + 88235.3sintheta

Explanation:

Wapplied = U* I *PF / 1000

where

Wapplied = real power (kilowatts, kW)

U = voltage (volts, V) = 600V

I = current (amps, A) = ?

PF = power factor = 0.85

I = Wapplied * 1000/ U * PF

I = (75 * 1000)/(600*0.85)

I = 147.058

Power = IV

Complex power (s) = IVcos thetha + IV sinthetha

Complex power (s) = 88235.3costheta + 88235.3sintheta

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