Answer:
Answer is 0.444 (or) 4/9
Step-by-step explanation:
Given data representes
No.of boys = 20
No. of girls =16
Total students = 36 (20+16)
Therefore n(S)=36
[tex]let \: A \: be \: an \: event \: of \: selecting \: a \: girl \\ n(A) = 16 \\ to \: find \: p(A) \\ p(A) = \frac{n(A)}{n(S)} \\ = \: \frac{16}{36} \\ on \: cancelling \: we \: get \: \frac{4}{9} \: \: or \: 0.444[/tex]
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