Answer:
x = [tex]-\frac{4}{3} , 3[/tex]
Step-by-step explanation:
We can factor [tex]3x^{2} -5x-12[/tex] into two factors like below. (Notice how they can't be simplified any further.)
(3x + 4) (x - 3)
Now we need to find out what value of x would satisfy the equation, or make the problem equal to 0. If we multiply [tex]-\frac{4}{3}[/tex] by 3, and add it to 4, then that equals 0. So, that must be one of the values of x. Next, if we replace x with 3 in the next factor, then it is 3-3, which equals 0 as well. So, that must be a solution as well.
This brings us to our solution of x = [tex]-\frac{4}{3}[/tex] and 3. Hope this made sense, not sure if I explained it that well.
