Answer:
The number of tigers decays by a factor of
[tex]\dfrac{4}{5}[/tex] every 0.50 years
Explanation:
The correctly written function is
[tex]N(t)=650\cdot \bigg(\dfrac{16}{25}\bigg)^t[/tex]
Convert 16/25 into its equivalent form (4/5)²
[tex]N(t)=650\cdot \bigg(\dfrac{4}{5}\bigg)^{2t}[/tex]
If you make t = 1/2, this is half-year, the population of tigers will decay by a factor of 4/5 in that time. Every time the half-year passes, the population is multiplied by 4/5, which means that the polulation will decay by a factor of 4/5 whenever half a year elapses.
Hence, the number of tigers decays by a factor of 4/5 every 0.50 years.
Answer:
0.50 years
Step-by-step explanation:
got it correct on khan
